Ministral 3 8B on Beginner board 1

1. Openingthe same for every model
2. Turn 10 of 8 applied · 0 opened · 8 refused
3. Turn 23 of 3 applied · 2 opened · hit a mine
4. The endevery mine shown

The end of its last reply

ep to identify safe cells to reveal.

### Observations:
1. **Row 3**: The three open cells (3,4), (3,5), and (3,6) all show a value of 1. This means each of these cells has exactly one mine adjacent to it.
   - For (3,4), the adjacent cells are (2,3), (2,4), (2,5), (3,3), (3,5), (4,3), (4,4), (4,5).
   - For (3,5), the adjacent cells are (2,4), (2,5), (2,6), (3,4), (3,6), (4,4), (4,5), (4,6).
   - For (3,6), the adjacent cells are (2,5), (2,6), (2,7), (3,5), (4,5), (4,6), (4,7).

2. **Row 4**: The open cells (4,4) and (4,6) show values of 2 and 1 respectively.
   - For (4,4), the adjacent cells are (3,3), (3,4), (3,5), (4,3), (4,5), (5,3), (5,4), (5,5).
   - For (4,6), the adjacent cells are (3,5), (3,6), (4,5), (4,7), (5,5), (5,6), (5,7).

3. **Row 5**: The open cells (5,4) and (5,5) show values of 2 and 2 respectively.
   - For (5,4), the adjacent cells are (4,3), (4,4), (4,5), (5,3), (5,5), (6,3), (6,4), (6,5).
   - For (5,5), the adjacent cells are (4,4), (4,5), (4,6), (5,4), (5,6), (6,4), (6,5), (6,6).

### Logical Deductions:
- The cell (2,4) cannot have a mine because it is adjacent to (3,4), which has a value of 1. If (2,4) had a mine, then (3,4) would have at least one mine adjacent to it (which it does), but we need to check if it is the only mine adjacent to (3,4). Since (3,4) has a value of 1, only one adjacent cell can have a mine. We can check other adjacent cells to see if they could be the mine.

- Similarly, (2,5) cannot have a mine because it is adjacent to (3,5), which also has a value of 1. If (2,5) had a mine, it would be the only mine adjacent to (3,5).

- (2,6) is adjacent to (3,6), which has a value of 1. If (2,6) had a mine, it would be the only mine adjacent to (3,6).

- (4,3) cannot have a mine because it is adjacent to (4,4) which has a value of 2. If (4,3) had a mine, it would need another mine adjacent to (4,4) to make the total 2.

- (4,7) cannot have a mine because it is adjacent to (4,6) which has a value of 1. If (4,7) had a mine, it would be the only mine adjacent to (4,6).

- (5,3) cannot have a mine because it is adjacent to (5,4) which has a value of 2. If (5,3) had a mine, it would need another mine adjacent to (5,4).

- (5,7) cannot have a mine because it is adjacent to (5,6) which has a value of 2. If (5,7) had a mine, it would need another mine adjacent to (5,6).

- (6,4) cannot have a mine because it is adjacent to (5,4) and (5,5), both of which have values of 2 and 2 respectively. If (6,4) had a mine, it would need to be accounted for in both counts.

- (6,5) cannot have a mine because it is adjacent to (5,4) and (5,5), both of which have values of 2 and 2 respectively. If (6,5) had a mine, it would need to be accounted for in both counts.

### Safe Cells to Reveal:
- (2,4), (2,5), (2,6), (4,3), (4,7), (5,3), (5,7), (6,4), and (6,5) are all safe to reveal based on the above reasoning.

<actions>
reveal 2 4
reveal 2 5
reveal 2 6
reveal 4 3
reveal 4 7
reveal 5 3
reveal 5 7
reveal 6 4
reveal 6 5
</actions>