Qwen3.8 Flash-Next on Daily opening jar 1
Reached the drop cap after 60 drops with 422 points, against the reference bot's 458 on the same jar. All of Qwen3.8 Flash-Next's games.
RESULTReached the drop cap
POINTS422
VS BOT92
LARGEST PIECENeptune
CLAMPED0
MODEL TIME235.5 min
COSTlocal, no list price
TOKENS IN / OUT45,986 / 219,198
REQUESTS60
Every drop
Where it let each piece go, what merged as a result and the running score. The jar is 108 units wide. The game file carries an arcade-session/1 envelope: the seed and these drops replay this exact jar at Starjar commit b2ac8ec.
| Drop | Piece | Where (0 to 108) | Made | Chain | Points | Score | Settled | |
|---|---|---|---|---|---|---|---|---|
| 1 | Stardust | 54.0 | none | 0 | 0 | at rest | ReplyFor the first drop in an empty jar, I want to place it in the center to establish a balanced foundation and give myself flexibility for subsequent drops on either side. <drop>54.0</drop> | |
| 2 | Stardust | 54.0 | Comet | 1 | 1 | 1 | at rest | Reply<drop>54</drop> |
| 3 | Stardust | 63.0 | none | 0 | 1 | at rest | Replyrrent state, I have a single Comet at x=54 on the floor. I'll drop this Stardust to the right of the Comet so it settles beside it, keeping the pile compact and building toward future merges. The Stardust should roll to rest at approximately x=62 (8.2 units from the Comet's center). <drop>63</drop> | |
| 4 | Comet | 54.0 | Asteroid | 1 | 3 | 4 | at rest | ReplyLooking at the board, I have a Comet at x=54. Dropping my Comet directly onto it will cause them to touch and fuse into an Asteroid, scoring 3 points. <drop>54</drop> |
| 5 | Stardust | 63.9 | Comet | 1 | 1 | 5 | at rest | ReplyLooking at the board, I have a Stardust at x=63.9 on the floor. I'll drop my Stardust directly on top of it to merge them into a Comet. <drop>63.9</drop> |
| 6 | Moon | 57.5 | none | 0 | 5 | at rest | ReplyComet at x=64.4 (gap between them ≈13.3) - Moon has radius 7.9, so I need sum-of-radii = 14.2 from Asteroid or 12.7 from Comet to touch The jar is mostly empty, so I'll drop the Moon between the existing pieces to fill the gap and create a stable, centered base for future merges. <drop>57.5</drop> | |
| 7 | Asteroid | 36.0 | Moon | 1 | 6 | 11 | at rest | Reply36 on the floor - Comet (r=4.8) at x=62.1 on the floor - Moon (r=7.9) at x=82.5 on the floor I'm holding an Asteroid. Dropping it directly onto the existing Asteroid at x=36 will cause them to merge into a Moon (3 points), and give me two Moons that could potentially merge later. <drop>36</drop> |
| 8 | Comet | 62.1 | Asteroid | 1 | 3 | 14 | at rest | ReplyLooking at the board, I have two Moons far apart (x=36 and x=81.8) that can't easily be connected, and a single Comet at x=62.1 in between. The best immediate play is to drop the Comet on top of the existing Comet to fuse them into an Asteroid (3 points) and clear space. <drop>62.1</drop> |
| 9 | Stardust | 62.0 | none | 0 | 14 | at rest | Replyand an Asteroid in the middle (x=62.1). The best strategy is to build up pieces on the Asteroid, working toward fusions. Dropping the Stardust directly on top of the Asteroid keeps the center active and builds toward a potential Moon that could roll toward one of the existing Moons. <drop>62</drop> | |
| 10 | Stardust | 46.5 | Comet | 1 | 1 | 15 | at rest | ReplyLooking at the board, I have a Stardust at x=46.5. I'm holding another Stardust, so I should drop it right on top to merge them into a Comet. <drop>46.5</drop> |
| 11 | Stardust | 46.0 | none | 0 | 15 | at rest | Replyloor between the left Moon and the Comet With a Stardust, I should keep it low and consolidated toward the center. Dropping it in the gap between the left Moon and the Comet will let it settle on the floor without adding height, and keeps pieces somewhat centered for future merges. <drop>46</drop> | |
| 12 | Stardust | 46.0 | Comet | 1 | 1 | 16 | at rest | Replyooking at the board, I have two Moons far apart (x=25.5 and x=81.8) and a small cluster in the middle. The best immediate move is to merge my held Stardust with the existing Stardust at x=46 to create a Comet, building up the center column toward eventually connecting the two Moons. <drop>46</drop> |
| 13 | Stardust | 51.0 | none | 0 | 16 | at rest | Replym and the right Moon My strategy: build up in the center to create a bridge/path between the two Moons. Dropping the Stardust between the two Comets (centered around x=51) will land on top of them and start building a column in the middle that can eventually connect the two halves. <drop>51</drop> | |
| 14 | Stardust | 54.3 | Comet, Asteroid | 2 | 6 | 22 | at rest | ReplyLooking at the board, I have a Stardust sitting at x=54.3, y=12.9 on top of the Comet at x=56.1. If I drop my Stardust right on top of it, they should fuse into a Comet, which could then roll and touch the Comet at x=56.1, creating a chain Asteroid (2x multiplier). <drop>54.3</drop> |
| 15 | Asteroid | 37.0 | Moon, Mars | 2 | 21 | 43 | at rest | Replymy Asteroid at x=37, it lands on the existing Asteroid → they merge into a Moon (3 points). That new Moon would then touch the existing Moon at x=22.8 (distance ~14.2 < sum of radii 15.8), triggering a chain: Moon + Moon → Mars (10 × 1.5 = 15 points). Total: 18 points from one drop! <drop>37</drop> |
| 16 | Moon | 81.8 | Mars | 1 | 10 | 53 | at rest | Replyx=81.8 on the right side. If I drop my Moon directly onto it, they should touch and fuse into a Mars (worth 10 points). The existing Moon at x=81.8, y=7.9 is sitting on the floor with nothing blocking directly above it, so a drop should land cleanly on top and trigger the fusion. <drop>81.8</drop> |
| 17 | Comet | 51.9 | Asteroid | 1 | 3 | 56 | at rest | Replycombined radii of 12.6 — just barely touching! If I drop my Comet right on top of the existing Comet at x=51.9: 1. Comet + Comet → Asteroid (3 points) 2. That new Asteroid touches the existing Asteroid → Moon (chain ×1.5 = 9 points) Total potential: 12 points from a single drop! <drop>51.9</drop> |
| 18 | Moon | 58.8 | none | 0 | 56 | at rest | Replye Moon will rest in the valley between both Asteroids (it can touch both) 3. Sets up future drops to create chains on top 4. Keeps the Mars pieces available for a later fusion push The midpoint between the asteroids is x = (51.5 + 66)/2 = 58.75, which is the optimal landing spot. <drop>58.8</drop> | |
| 19 | Comet | 63.0 | none | 0 | 56 | at rest | Replyto consolidate toward the center. The Moon (x=54.3) is touching the left Asteroid (x=40.1), but there's a gap (~4.6 units at surface) between the Moon and the right Asteroid (x=73.1). Dropping the Comet in that gap will help bridge the middle and push things toward consolidation. <drop>63.0</drop> | |
| 20 | Asteroid | 51.0 | Moon | 1 | 6 | 62 | at rest | Replyenter organized, leaves room on both sides, and positions things for future merges. The pile is still low (19.4), so there's no urgency - focus on structure. Dropping on the Moon creates a stable position that won't roll away, and keeps the center clear for potential future merges. <drop>51</drop> |
| 21 | Moon | 80.0 | Mars, Earth | 2 | 33 | 95 | at rest | Replyon to create a Mars, that new Mars could roll toward the existing Mars at x=92.3 for a chain! Dropping at x=80 should land on/near the Moon at x=74.8, triggering a Moon+Moon→Mars fusion. The resulting Mars will be elevated and likely roll right toward the existing Mars at x=92.3. <drop>80.0</drop> |
| 22 | Comet | 62.2 | Asteroid | 1 | 3 | 98 | at rest | ReplyLooking at the board, I can see a Comet already at x=62.2. If I drop my Comet directly on top of it, they'll touch and fuse into an Asteroid (3 points), which also helps consolidate the pile. <drop>62.2</drop> |
| 23 | Asteroid | 48.0 | Moon, Mars | 2 | 21 | 119 | at rest | ReplyMoon + Moon = Mars (6 × 1.5 = 9 points, chain bonus) - Total: 12 points Dropping at x=48 places it at distance 12.2 from the Asteroid at x=35.8 (need ≤12.6 to touch), fusing them. The resulting Moon at ~x=42 is only ~8 units from the Moon at x=49.9 (need ≤15.8), causing the chain. <drop>48</drop> |
| 24 | Comet | 30.7 | none | 0 | 119 | at rest | Replyhave two Mars pieces at x=18.6 and x=42.8 with a gap of only 4.8 units between their edges. A Comet (diameter 9.6) won't fit in that gap on the floor, so it will bridge nicely on top of both Mars pieces. This keeps the board compact and creates a stable platform for future merges. <drop>30.7</drop> | |
| 25 | Moon | 35.0 | none | 0 | 119 | at rest | Replyrth at x=86.8 on the right No immediate fusion is possible with a Moon (no other Moon present). I should drop it centrally to keep the pile compact and maintain flexibility for future drops. Dropping at x=35 places it on top of the Comet, keeping the formation tight and centered. <drop>35.0</drop> | |
| 26 | Moon | 32.7 | Mars, Earth | 2 | 33 | 152 | at rest | Replyew Moon directly on top of the existing Moon. Their centers will be 15.8 apart (7.9 + 7.9), triggering a fusion into a Mars. I verified this won't cause any unwanted collisions with the Mars at (15.3) or Comet at (42.7) since the fusion point is high enough (y≈28.4) to avoid them. <drop>32.7</drop> |
| 27 | Stardust | 72.0 | none | 0 | 152 | at rest | Replyces My strategy: Build upward on the right-center cluster (Mars/Asteroid area) to create a dense column that can efficiently merge pieces together. Dropping near the Asteroid at x≈72 lets it land on or beside the Asteroid, keeping pieces compact and building toward larger merges. <drop>72.0</drop> | |
| 28 | Mars | 56.4 | Earth | 1 | 15 | 167 | at rest | Replymy Mars directly on top of it, they'll touch and fuse into an Earth (worth 15 points). After the fusion, I'll have three Earths on the board (the two on the floor at x=23.9 and x=89.7, plus the new one near x=56.4, y=29.1), giving me great future matching potential for Neptunes. <drop>56.4</drop> |
| 29 | Mars | 38.9 | none | 0 | 167 | at rest | Replyx=70.5 The gap between the first two Earths (x=21.9 and x=55.8) is a good spot to place the Mars. It will land on top of both Earths, keeping things compact and leaving the right side open for future drops. The center between those two Earths is at x = (21.9 + 55.8) / 2 ≈ 38.85. <drop>38.9</drop> | |
| 30 | Stardust | 78.6 | Comet | 1 | 1 | 168 | at rest | ReplyLooking at the board, I can see a lone Stardust at x=78.6. Dropping my Stardust directly on top of it will cause them to merge into a Comet, which is a clean and efficient play. <drop>78.6</drop> |
| 31 | Mars | 35.4 | Earth, Neptune | 2 | 47 | 215 | at rest | ReplyEarth for 10 points. - This creates a 4th Earth on the board (joining the ones at x=14.3, 59.4, and 93.4), which is strategically valuable for building toward Neptune/Saturn merges later. - The resulting Earth will settle safely in the lower portion of the jar, well below the rim. <drop>35.4</drop> |
| 32 | Comet | 77.6 | Asteroid, Moon | 2 | 12 | 227 | at rest | Replynd lands on the existing Asteroid (they're already stacked) → **Moon** (chain! 6 × 1.5 = 9 points) **Chain total:** 3 (Asteroid) + 9 (chain Moon) = **12 points** The resulting Moon would settle nicely between the two Earths at around height 22, which is still well below the rim. <drop>77.6</drop> |
| 33 | Comet | 44.3 | Asteroid | 1 | 3 | 230 | at rest | ReplyLooking at the board, I have a Comet at x=44.3. Dropping my Comet directly on it will merge them into an Asteroid (6 points), clearing space and progressing the chain. The Comet's center is at x=44.3, and dropping straight down there should land it on top and trigger the merge. <drop>44.3</drop> |
| 34 | Stardust | 70.0 | none | 0 | 230 | at rest | ReplyStardust can settle usefully Since I can't merge anything directly with a Stardust, I'll place it to start building toward a future chain. The gap between the Earth (x=55.8) and Moon (x=78) is a good spot to begin stacking pieces that could eventually push the two Earths together. <drop>70</drop> | |
| 35 | Asteroid | 37.7 | Moon | 1 | 6 | 236 | at rest | Replyectly above the existing Asteroid that would block the drop. The nearest neighbors (Earth at x=54.8 and Neptune at x=18.9) are far enough away horizontally. After fusion, I'll have a Moon near x=37.7, which could potentially chain with the existing Moon at x=74.1 in future moves. <drop>37.7</drop> |
| 36 | Stardust | 68.7 | Comet | 1 | 1 | 237 | at rest | Replyto create a Comet (1 point), which could chain later. The pile is very low (29.1 vs rim at 164), so there's no urgency — just efficient merging. Dropping at x=68.7 will land the new Stardust right on top of the existing one (they're at the same x), causing a fusion into a Comet. <drop>68.7</drop> |
| 37 | Stardust | 50.0 | none | 0 | 237 | at rest | Replyial merges. The Earth at x=54.8 has its top at y=23.4, which is below the Neptune's top (y=29.1). Dropping the Stardust near the center-left will let it land on top of the Earth without raising the overall profile significantly, and keeps it away from the Comet on the right side. <drop>50.0</drop> | |
| 38 | Stardust | 32.1 | Comet | 1 | 1 | 238 | at rest | Replyat the board, I can see a Stardust at x=32.1. Dropping my Stardust directly on top of it will cause them to touch and fuse into a Comet (1 point), progressing the chain. The drop is straightforward — it falls straight down onto the existing Stardust which is sitting on the Moon. <drop>32.1</drop> |
| 39 | Moon | 44.0 | none | 0 | 238 | at rest | Replyx=44, where the Moon touches the Earth at approximately y=28 (contact angle ~33°, may roll slightly toward the top of the Earth). This keeps the pile relatively compact and the height low (top ≈ 36, still 128 units below the rim), while leaving room for future strategic placements. <drop>44</drop> | |
| 40 | Comet | 69.6 | Asteroid | 1 | 3 | 241 | at rest | Replytouching → fuse into an Asteroid (3 points) - The resulting Asteroid at ~(69.6, 24.5) won't overlap with anything else (Moon at 74.4 is too far, Earths are too far) - The pile top stays at 35.4 (the Moon at x=43.6) This is a clean fusion that reduces piece count and gains points. <drop>69.6</drop> |
| 41 | Comet | 33.0 | Asteroid | 1 | 3 | 244 | at rest | Replythe Moon at x=36. If I drop my Comet right on top of it, they'll touch and fuse into an Asteroid (3 points). The Moon at x=43.7 (y=27.5) is nearby but won't prevent the fusion — the dropped Comet will land on/near the existing Comet and they'll merge before the Moon can interfere. <drop>33</drop> |
| 42 | Mars | 80.0 | none | 0 | 244 | at rest | Reply6) and the Earth at x=93.4 (left edge ~81.7). Dropping the Mars at x=80 will bridge this gap, landing on/near the Earth at x=93.4 and consolidating the right side. This keeps the pile compact and creates a stepping stone that could help push things toward a future Earth-Earth merge. <drop>80</drop> | |
| 43 | Comet | 46.4 | none | 0 | 244 | at rest | Replyof the Moon at x=46.4. This: - Creates a stable central tower - Sets up potential Comet-Comet merges that could cascade into Asteroids, potentially reaching the Asteroids at x=34.2 or x=73.9 - Keeps the jar balanced - Leaves plenty of room (top would be ~42, well below rim at 164) <drop>46.4</drop> | |
| 44 | Asteroid | 73.6 | Moon, Mars | 2 | 21 | 265 | at rest | Replys: one at (73.6, 22.1) and one at (34.2, 22). Dropping my Asteroid at x=73.6 will land it on top of the existing Asteroid there, causing them to fuse into a Moon (6 points). The path is clear - the Comet (at x=46.3) and Mars (at x=98.3) are far enough away not to block the drop. <drop>73.6</drop> |
| 45 | Comet | 26.4 | Asteroid, Moon, Mars | 3 | 32 | 297 | at rest | Replytop of it to trigger a merge into an Asteroid (3 points), and potentially set up a chain with the nearby Asteroid at x=34.2. The existing Comet sits on the Asteroid at (34.2, 22), so merging Comets creates a new Asteroid that may roll into the existing Asteroid for a chain bonus. <drop>26.4</drop> |
| 46 | Moon | 88.0 | none | 0 | 297 | at rest | Replyw Mars could touch the existing Mars at x=98.3, creating an Earth, which could then touch the Earth at x=96.3 — a chain reaction! Dropping at x=88 should land the Moon on the right side of the pile, in contact with (or very close to) the Mars at x=98.3, setting up a future chain. <drop>88.0</drop> | |
| 47 | Stardust | 68.8 | none | 0 | 297 | at rest | Replyategy:** Place the Stardust on top of the Moon at x=68.8. This: - Builds up the center-right area toward the Mars at (83.8, 34.9) - Creates a platform for future drops that could help bring Mars pieces together - Keeps the pile relatively compact without creating a dangerous spike <drop>68.8</drop> | |
| 48 | Comet | 47.0 | none | 0 | 297 | at rest | Replyth (x=55) where a small piece could settle nicely - I want to avoid building height near the top pieces (Mars at x=83.8, y=34.9) Dropping between the Mars at x=38.5 and Earth at x=55 will fill a gap without creating unnecessary height, and keeps the board compact for future merges. <drop>47</drop> | |
| 49 | Stardust | 61.6 | Comet, Asteroid | 2 | 6 | 303 | at rest | Reply=34.4. Dropping my Stardust directly onto it will create a Comet merge (1 point). Let me verify this is the best option. The only other Stardust on the board is at (61.6, 34.4), so that's my only immediate merge opportunity. I'll drop directly on top of it to guarantee the merge. <drop>61.6</drop> |
| 50 | Moon | 68.8 | Mars, Earth, Neptune | 3 | 75 | 378 | at rest | Replytop and merge to create a Mars. That new Mars (at ~x=68.8, y=33.5) would be within touching distance of the Mars at x=83.8, y=34.9 (distance ≈15.1, sum of radii = 19.4), triggering a chain! Chain: Moon+Moon→Mars (6 pts), then Mars+Mars→Earth (15×1.5=22.5 pts) ≈ 28.5 points total. <drop>68.8</drop> |
| 51 | Stardust | 65.0 | none | 0 | 378 | at rest | Replyst is tiny (radius 3.5) and won't create any matches, I want to place it where it settles into a gap without adding much height. Dropping it around x=65 should let it roll down into the area between the Neptune (x=54.4) and Mars (x=75.9), filling a gap on the right side of the pile. <drop>65</drop> | |
| 52 | Comet | 72.5 | none | 0 | 378 | at rest | Replyl "valley" at about x=72.5, y≈23.8 - This position is low, stable, and won't overlap the Stardust at x=81.8 The equilibrium point between the Neptune and Mars for a Comet of radius 4.8 is approximately (72.5, 23.8) — a nice low resting spot that won't add much to the pile height. <drop>72.5</drop> | |
| 53 | Stardust | 81.8 | Comet, Asteroid | 2 | 6 | 384 | at rest | Replyr Stardust directly onto it will cause them to fuse into a Comet, making progress up the chain. Since the gap at that x-position is clear (the Comet's right edge is at 78.6 and the Earth's left edge is at 84.4), a Stardust dropped at x=81.8 will fall cleanly onto the existing one. <drop>81.8</drop> |
| 54 | Stardust | 62.0 | none | 0 | 384 | at rest | Reply- The right side is too packed (Earth and Mars overlap horizontally). **Best move:** Drop into the gap between Neptune and Mars at around x=62. The Stardust will roll down the Neptune's surface and settle low in the crevice between these two pieces, keeping the pile height minimal. <drop>62</drop> | |
| 55 | Asteroid | 80.3 | Moon | 1 | 6 | 390 | at rest | Replynew Mars would then be close enough to the existing Mars at (75.9, 9.7) to trigger a chain merge into an Earth! - Asteroid + Asteroid → Mars: 3 points - Mars + Mars → Earth (chain ×1.5): 22.5 points - Total potential: ~25.5 points Dropping right on top of the Asteroid at x=80.3. <drop>80.3</drop> |
| 56 | Stardust | 68.4 | Comet | 1 | 1 | 391 | at rest | Replyt at (68.4, 29.7) that's wedged between the Neptune and the Moon. I'll try to drop my Stardust right on top of it to create a merge. Even though the surface is curved, the wedging effect of the surrounding pieces should help stabilize the new piece on top long enough for a fusion. <drop>68.4</drop> |
| 57 | Mars | 33.3 | Earth | 1 | 15 | 406 | at rest | Replyjar. If I drop my held Mars directly on top of the one at x=33.3, they should merge into an Earth for 15 points. The Mars at (33.3, 30.1) has its top at y=39.8, with open space above it. Dropping straight down at x=33.3 should land the new Mars right on top, triggering the merge. <drop>33.3</drop> |
| 58 | Asteroid | 50.0 | Moon | 1 | 6 | 412 | at rest | Replys at x=50, so dropping directly on top at x=50 will create the fusion - After fusion, a Moon (radius 7.9) appears at the contact point around (50, 45.5) - No chain is possible since the next Moon is too far away - With only 2 drops left, taking guaranteed points is the best strategy <drop>50</drop> |
| 59 | Stardust | 54.0 | none | 0 | 412 | at rest | Replyarance) - No other Stardust exists to fuse with, so this piece will simply settle - This is near the end of the game with plenty of headroom Since no fusion is possible, I'll drop it in a central position where it will settle stably without causing height issues for the final drop. <drop>54</drop> | |
| 60 | Moon | 42.0 | Mars | 1 | 10 | 422 | at rest | Replyance from that position to the top Moon at (51.3, 40.6) is only ~12.4, which is well within the touch distance of 15.8 (two Moons' radii). They'll fuse into a Mars for 10 points! The Moon would roll slightly right on the Earth's curved surface toward the top Moon, ensuring contact. <drop>42</drop> |