Qwen3.5 9B on Tricky grid 2
No readable grid: 0 of 57 blank cells right. All of Qwen3.5 9B's answers.
RESULTNo readable grid
CELLS RIGHT0 / 57
SAIDn/a
MODEL TIME3.6 min
COSTlocal, no list price
TOKENS IN / OUT1,609 / 3,000
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5 given 5 filled correctly 53 wrong, with the right digit 3 left empty
The end of its reply
.8....75.....97..3..256.......6.1...3..2....5..6.7..9....` Parsing: R1: `...........1` -> 8 dots, then 1. So R1C9=1. Grid: . . . . . . . . 1 R2: `3.527.4..` -> 3 . 5 | 2 7 . | 4 . . R3: `...4..8.` -> Wait, let's look at the chars count. The string is continuous. Let's break it into chunks of 9. Chunk 1 (R1): `...........1` -> Length 10? No. Let's recount the input string length. `...........1` is 10 characters? `.`x8 + `1` = 9 chars. Ah, `.......` (7 dots) + `..1` (2 dots, 1)? Input: `...........1` Let's assume standard Sudoku spacing isn't in the single line string. The prompt says: "Same puzzle as one line of 81 characters". Let's count the dots in `...........1`. If it is 81 chars total, each row is 9 chars. Row 1: `...........1`? That looks like 10 chars. Maybe the first part is `.......` (7) then `. . 1`? Let's look at the visual again: `... ... ..1`. This implies Row 1 Col 1-3 are empty, Col 4-6 are empty, Col 7-8 empty, Col 9 is 1. So R1: `.......` (7 dots) then `1`? No, `..1` means two dots then a 1. So R1: `.` `.` `.` `.` `.` `.` `.` `.` `1`. That's 8 dots and a 1. Total 9 chars. Okay, R1 = `.......` (7) + `.` (8) + `1` (9)? No. Visual: `...` (3) `...` (6) `..1` (9). So R1 = `. . . . . . . . 1`. Row 2: `3.5 27. 4..` Block 1: `3.5` -> `3`, `.`, `5`. Block 2: `27.` -> `2`, `7`, `.`. Block 3: `4..` -> `4`, `.`, `.`. R2 = `3 . 5 2 7 . 4 . .` Row 3: `... .4. .8.` Block 1: `...` -> `. . .` Block 2: `.4.` -> `.`, `4`, `.` Block 3: `.8.` -> `.`, `8`, `.` R3 = `. . . . 4 . . 8 .` Row 4: `... 75. ...` Block 1: `...` -> `. . .` Block 2: `75.` -> `7`, `5`, `.` Block 3: `...` -> `. . .` (Wait, the visual has `...` at the end? Or is it empty?) Visual: `... 75. ...` -> Spaces separate blocks. Block 1: `...` Block 2: `75.` Block 3: `...`? The text says `...` then space then `75.` then space then `...`. So R4 = `. . . 7 5 . . . .` Row 5: `.97 ..3 ..2` Block 1: `.97` -> `.`, `9`, `7` Block 2: `..3` -> `.`, `.`, `3` Block 3: `..2` -> `.`, `.`, `2` R5 = `. 9 7 . . 3 . . 2` Row 6: `56. ... ...` -> Wait, visual says `56. ... ...`? Prompt visual: `.97 ..3 ..2` (Row 5) `56. ... ...` (Row 6)? No, let's check the single line again. `...75.....97..3..256.......6.1...3..2....5..6.7..9....` Let's parse the single line carefully starting from index 0. 0-8: `...........1` (Row 1) -> `.......` + `.` + `1`? No, count chars. String: `...........1` Count: 1,2,3,4,5,6,7,8 dots, then '1'. Total 9 chars. So R1 = `. . . . . . . . 1`. 9-17: `3.527.4..` (Row 2) Chars: `3`, `.`, `5`, `2`, `7`, `.`, `4`, `.`, `.`. Correct. 18-26: `...4..8.` (Row 3)? Let's check the single line substring at 18. Indices 18,19,20,21,22,23,24,25,26. String from prompt: `...........13.527.4......4..8....75.....97..3..256.......6.1...3..2....5..6.7..9....` Let's slice it manually. 0-8: `...........1` (Wait, 8 dots + 1 = 9). Correct. 9-17: `3.527.4..` (9 chars). Correct. 18-26: `...4..8.` ? Let's look at the remaining string after R2: `......4..8....75.....97..3..256.......6.1...3..2....5..6.7..
Grid tricky-1 of set v1, 24 givens. Puzzle as one line: ........13.527.4......4..8....75.....97..3..256.......6.1...3..2....5..6.7..9....