Qwen3.5 9B on Devious grid 2
Left cells empty: 0 of 55 blank cells right. All of Qwen3.5 9B's answers.
RESULTLeft cells empty
CELLS RIGHT0 / 55
SAIDn/a
MODEL TIME2.5 min
COSTlocal, no list price
TOKENS IN / OUT315 / 1,500
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5 given 5 filled correctly 53 wrong, with the right digit 3 left empty
The end of its reply
...95..4.62..3........6.2...74......1..8..76..4.67....785....19........`
Let's re-parse based on standard Sudoku input where dots are empty cells.
Row 1: `.....4283`? No, looking at the text "Puzzle (26 givens...)".
Let's count characters in the provided block:
Row 1: `. . . . . . 4 2 8 3` (Wait, the text says `... ..4 283` which might be spaced).
The compact line is: `.....4283....95..4.62..3........6.2...74......1..8..76..4.67....785....19........`?
Let's try to map the visual grid provided in the text block first to ensure accuracy.
Text:
```
... ..4 283
... .95 ..4
.62 ..3 ...
... ..6 .2.
..7 4.. ...
.1. .8. .76
..4 .67 ...
.78 5.. ..1
9.. ... ...
```
Let's convert this to a grid:
R1: `.` `.` `.` | `.` `.` `.` | `4` `2` `8` ? No, the last group is `283`.
Actually, looking at spacing: `...` (3) `..4` (3) `283` (3).
So R1: `.`, `.`, `.`, `.`, `.`, `.`, `4`, `2`, `8`, `3`? That's 10 chars.
Let's re-read carefully: `... ..4 283`.
Maybe the spaces are just separators in the description, but the compact line is definitive.
Compact Line: `....4283....95..4.62..3........6.2...74......1..8..76..4.67....785....19........` (This was my hypothesis).
Let's re-examine the string provided: `.....4283....95..4.62..3........6.2...74......1..8..76..4.67....785....19........`
Wait, the first part of the compact line in my thought trace above was `.....`. Let's count dots.
Let's use the visual block again, assuming standard single character per cell (ignoring spaces for parsing):
Row 1: `. . . . . . 4 2 8` ... wait, where is the 3?
The text says: `... ..4 283`.
If we remove spaces: `...` + `..4` + `283` = `.....4283`. That's 9 characters.
Let's verify: `.` `.` `.` | `.` `.` `4` | `2` `8` `3`. Yes, that fits Row 1 having givens at cols 7,8,9 as 4,2,8? Or is it `2`, `8`, `3`?
"283" implies cells 7, 8, 9 are 2, 8, 3.
So Row 1: `. . . . . . 2 8 3`.
Let's re-parse the visual block row by row removing spaces:
R1: `...` `..4` `283` -> `.....4283`? No, `..4` is dot-dot-4. `283` is 2-8-3.
Combined: `.` `.` `.` `.` `.` `4` `2` `8` `3`. (Length 9).
Givens: R1C6=4, R1C7=2, R1C8=8, R1C9=3.
R2: `...` `.95` `..4` -> `... .95 ..4` -> `...` + `.` + `9` + `5` + `.` + `.` + `4`.
Combined: `.` `.` `.` `.` `9` `5` `.` `.` `4`.
Givens: R2C5=9, R2C6=5, R2C9=4.
R3: `.62` `..3` `...` -> `.62` + `.` + `.` + `3` + `.` + `.` + `.`.
Combined: `.` `6` `2` `.` `.` `3` `.` `.` `.`.
Givens: R3C2=6, R3C3=2, R3C6=3.
R4: `...` `..6` `.2.` -> `...` + `.` + `.` + `6` + `.` + `2` + `.`.
Combined: `.` `.` `.` `.` `.` `6` `.` `2` `.`.
Givens: R4C6=6, R4C8=2.
R5: `..7` `4..` `...` -> `..7` + `4` + `.` + `.` + `.`.
Combined: `.` `.` `7` `4` `.` `.` `.` `.` `.`.
Givens: R5C3=7, R5C4=4.
R6: `.1.` `.8.` `.76` -> `.1.` + `.` + `8` +Grid devious-1 of set v1, 26 givens. Puzzle as one line: .....4283....95..4.62..3........6.2...74......1..8..76..4.67....785....19........